Solution
X-ray beam has ?=.01 nm = 10 pm
?` - ? =(h/mec) (1 - cos?)
= ?c (1 - cos?) ?c is Compton wavelength of the electron
(a) ??=(h/cme)(1-cos(180))= 2h/cme =2(6.63x10-34)/[(3x108)(9.11x10-31)] =2(2.43 pm)= 4.86 pm
(b) ?E={ hc/ ?` -hc/?} =(6.63x10-34)(3x108){1/14.86 -1/10}/(10-12) =-.65x10-14 J = -.41x105 eV = -41 keV