Problem
fundamental of A has LA=?/2=v/2f =(343m/s)/2(300Hz) =.572 m
2nd harmonic has LA=?=.572m f=v/? =343/.572=600Hz
3rd harmonic of pipe B has n=3
v= ? f=(4 LB/3)600 =343 m/s
LB = 343/800 = .429 m
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